water_latent_heat_sublimation#
- metpy.calc.water_latent_heat_sublimation(temperature)[source]#
Calculate the latent heat of sublimation for water.
Accounts for variations in latent heat across valid temperature range.
- Parameters:
temperature (
pint.Quantity
)- Returns:
pint.Quantity
– Latent heat of vaporization
Examples
>>> from metpy.calc import water_latent_heat_sublimation >>> from metpy.units import units >>> water_latent_heat_sublimation(-15 * units.degC) <Quantity(2837991.13, 'joule / kilogram')>
Notes
\[L_s = L_{s0} - (c_{pl} - c_{pv}) (T - T_0)\]Eq 18, [Ambaum2020], using MetPy-defined constants in place of cited values.