water_latent_heat_sublimation#

metpy.calc.water_latent_heat_sublimation(temperature)[source]#

Calculate the latent heat of sublimation for water.

Accounts for variations in latent heat across valid temperature range.

Parameters:

temperature (pint.Quantity)

Returns:

pint.Quantity – Latent heat of vaporization

Examples

>>> from metpy.calc import water_latent_heat_sublimation
>>> from metpy.units import units
>>> water_latent_heat_sublimation(-15 * units.degC)
<Quantity(2837991.13, 'joule / kilogram')>

Notes

\[L_s = L_{s0} - (c_{pl} - c_{pv}) (T - T_0)\]

Eq 18, [Ambaum2020], using MetPy-defined constants in place of cited values.