Bulk Shear#

Use functions from metpy.calc as well as pint’s unit support to perform calculations.

The code below uses example data from our test suite to calculate the bulk shear over the lowest three kilometers for the provided sounding data.

import pandas as pd

from metpy.calc import bulk_shear, wind_components
from metpy.cbook import get_test_data
from metpy.units import units

Upper air data can be obtained using the siphon package, but for this example we will use some of MetPy’s sample data.

# Set column names
col_names = ['pressure', 'height', 'temperature', 'dewpoint', 'direction', 'speed']

# Read in test data using col_names
df = pd.read_fwf(get_test_data('jan20_sounding.txt', as_file_obj=False),
                 skiprows=5, usecols=[0, 1, 2, 3, 6, 7], names=col_names)

Drop any rows with all NaN values for T, Td, winds

df = df.dropna(subset=('temperature', 'dewpoint', 'direction', 'speed'),
               how='all').reset_index(drop=True)

Isolate pressure, wind direction, wid speed, and height and add units

p = df['pressure'].values * units.hPa
wdir = df['direction'].values * units.degree
sped = df['speed'].values * units.knot
height = df['height'].values * units.meter

Calculate the u and v-components of the wind

u, v = wind_components(sped, wdir)

Compute the bulk shear for the lowest three km

print(bulk_shear(p, u, v, height, depth=3 * units.km, bottom=height[0]))

(<Quantity(21.9580223, 'knot')>, <Quantity(4.98986292, 'knot')>)

Total running time of the script: ( 0 minutes 0.018 seconds)

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